Why when i give "Im fine thanks" it gives: "Good"???

Question

y = input("How are u:")
if y == "Im fine"or "Good" or "Good!" or "Im fine!" or "Good." or "Im fine." or "I'm fine" or "I'm fine!" or "I'm fine" or "Im good":
print("Good")
elif y == "Im fine thanks":
print("No problem")
else:
print("What?")

Answer 1

А на русском?

Answer 2

Because you're asking if y==something...and then presenting a bunch of strings that all evaluate to True (without comparing them to anything)

say = "moo"
if say=="hello" or "mu": print("Condition 1 met")
if say=="hello" or say=="mu": print("Condition 2 met")

Output:
Condition 1 met

In the first condition, it's like you wrote this:
if (say=="hello") or ("mu"):
...

A non-empty string is "truthy" so evaluates as True, while empty strings are "falsy" and evaluate as False.

Answer 3

Your multiple ORs make a messy condition check for an interpreter. To make your script work as expected, you need to explicitly compare y with all the answer options. if (y==...) or (y=...) or ... To avoid typing a whole bunch of comparisons, i'd recommend you to use construction like this:

y = input("How are u:")
if y in ("Im fine", "Good", "Good!", "Im fine!", "Good." ,"Im fine." ,"I'm fine" ,"I'm fine!" , "I'm fine" ,"Im good"):
print("Good")
elif y == "Im fine thanks":
print("No problem")
else:
print("What?")

Answer 4

Joe
У тебя неверно прописаны условия в if - нужно явно сравнивать y с каждой строкой. В противном случае интерпретатор считает что условие всегда истинно и будет постоянно давать один и тот же результат. Я написал, как решить проблему.