Sum of finite series in C++

Question

Write a C++ program to find the sum of:
x+(x^3/2!)+(x^5/3!)+(x^7/4!)+...+(x^[2m-1]/m!)
For a random value of ‘m’.

Answer 1

[FIXED] That sequence looks broken to me, i.e. it doesn't match the generalization in at least two (edit: just one) spots (unless I'm missing something; cmiiw)

Answer 2

Ketan Lalcheta Ah, it's been fixed :) No worries.

Answer 3

it's correct.. Kirk Schafer ...no broken is found for me.. first term is x because 2m-1 /m! is 1 for m as 1...next steps are for m as 3 and 5, 2m-1/m! means (2*4)-1/ 5! is perfect for 7/5!