Display all these arrays at the end of the program.

Question

Question is this:
Write a c++ program that stores 20 numbers in two arrays A and B ie 10 numbers in each array. Declare another array C.Now, compare the elements of the two arrays A and B , and put all the numbers that do not have a duplicate, into the array C. Display all these arrays at the end of the program.

Answer 1

#include<iostream>
using namespace std;

int main(){
    int a[10],b[10],c[20],i,j;

    cout<<"Enter 10 numbers for A"<<endl;
    for(i=0;i<10;i++){
        cin>>a[i];
    }
    cout<<"Enter 10 numbers for B"<<endl;
    for(j=0;j<10;j++)
    {
        cin>>b[j];
    }
     for(int i=0;i<10;i++){
            for(int j=0;j<10;j++)
            {
               if(a[i]!=b[j]){
            c[i]=a[i];
        }
        cout<<c[i];
            }

     }

    return 0;

}

Answer 2

I tried this code , I think the output is wrong, please correct me

Answer 3

I dont think that you have to compare only items to same index of a and b for find a duplicated... Example:
a= [1,2,3]
b= [5,1,1]
c would be:
c= [2,3,5]

because duplicated cannot appear in same array and in different indices... I have right?

P.S. Save always code longer than 6-7 lines in 'Code Playground' section and post here his link... In this way we can help you better (without copy, reformat and execute all)

Answer 4

so, what would be the correct code?
I'm confused here

Answer 5

Suresh Thiyam Try to figure out yourself... You know that you have to compare ALL items in EITHER arrays (a and b). Then, how you can do this?

Hint: Think of either arrays like a single array

Futhermore you have think how you program have to handle c array... If all 20 items are different, no problem but what if there are duplicated items?

Hint: Here you have to use something for "signal" how many items of c are useful for you problem