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Why is my function not returning a value?
https://code.sololearn.com/c2aCps3Ye556/?ref=app Ive tried using pointers in my functions (call by reference) instead of calling by value but every time i try something out, it just doesnt work. Here in my code, ive tried returning a pointer from a function and then dereferencing it when calling it. Is it ok to do so? My program wont print anything and would actually generate a runtime error. But i cant seem to understand why that is the case. Kindly help🙏 Thanks!!
4 Respuestas
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Here's what I found:
1) You accidentally closed the main function with an extra }
2) when you use strcat() the first argument should be a string variable
3) I don't know why &inp[0] was used, just inp would've made more sense
4) *bracket_by_len() was not needed because the return type is a char array
+ 1
thanks alot jtrh and Bebida Roja That did indeed solve the problem.
I was making the mistake of storing the string "word" in a constant which is not possible.
@jtrh Thanks also for pointing out the other errors in my program. However, i do want to point out here that since my function returns a pointer, is it ok for me to simply write
return temp;
or do i have to create a seperate pointer for temp and then return it
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the first argument to strcat cannot be a constant, as the concatenation is stored in that address.
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This works if you wanna give special brackets to the end of the string with a certain length
#include <stdio.h>
#include <string.h>
char *bracket_by_len
( char *word, int size)
{
char temp[20000];
if (size<5)
{
strcpy(temp,"<<");
strcat(temp,word);
strcat(temp,">>");
}
else if (size>5 && size<10)
{
strcpy(temp,"(*");
strcat(temp,word);
strcat(temp,"*)");
}
else
{
strcpy(temp,"/+");
strcat(temp,word);
strcat(temp,"+/");
}
return temp ;
}
int main()
{
char inp[30];
printf("Enter a word: ");
scanf("%s",inp);
printf("%s",bracket_by_len(inp,strlen(inp)));
return 0;
}