Programa de datos de alumno, debe de imprimir la media, mediana y moda rede rente a la variable edad .. pero me brinda un error

Question

#include <iostream>
#include <cstdlib>
#include <windows.h>
#include <stdlib.h>

using namespace std;
struct persona{
string nombre;
string apellido;
int edad;
char genero;
};
int main()
{
cout<<endl<<"|************************************************************************************************|";
cout<<"\n";
cout<<"\t \t \t PROGRAMA DATOS DE ALUMNOS";
cout<<endl<<"|------------------------------------------------------------------------------------------------|";
cout<<"\n";
cout<<"\n";
cout<<"INGRESA EL NOMBRE Y LA EDAD DE 30 ALUMNOS PARA SABER LA MEDIA, MEDIANA Y MODA REFERENTE A LA VARIABLE EDAD: ";
cout<<"\n";
cout<<endl<<"|************************************************************************************************|";
cout<<"\n";
{

persona Estudiantes[5];
//INGRESO DE LOS DATOS DE LOS ALUMNOS
for(int e=0; e<5; e++)
{
cout<<"ingreso datos alumnos \t"<< e + 1;
cout<<"\n";
cout<<"ingreso nombre \t"; cin>>Estudiantes[e].nombre;
cout<<"ingreso apellido \t"; cin>>Estudiantes[e].apellido;
cout<<"ingreso edad \t"; cin>>Estudiantes[e].edad;
cout<<"ingreso genero M/F \t"; cin>>Estudiantes[e].genero;
cout<<"\n";

};
int Estudiantes[e].edad;
int media, moda, mediana, total;

for(int i=0; i<5; i++)
{
media=total/5;
total=Estudiantes[e].edad;
cout<<"El calculo de la media es:";
cin>>media;
};

for(int j=0; j<5; j++)
{
mediana= total=Estudiantes[e].edad;
cout<<"El calculo de la mediana es:";
cin>>mediana;
};

for(int k=0; k<5; k++)
{
moda=
total=total+Estudiantes[e].edad;
cout<<"El calculo de la moda es:";
cin>>moda;

};

system("pause");
return 0;
}
}

Me brinda error en int Estudiantes [e].edad, espero puedan apoyarme...

Answer 1

Your next problem is the value of Total.
You declare the variable.
And then divide it by 30
It does not have a value yet

Answer 2

so "e" I must put it out of [], as it would be in that case, sorry but I'm new to programming

Answer 3

I understood, thank you for explaining that, notice that at the time of running the program asks me to enter the media, mediana and moda .. I do not know if I do something wrong there so that it does not give me the result

Answer 4

now my code is like this

#include <iostream>
#include <cstdlib>
#include <windows.h>
#include <stdlib.h>

using namespace std;
struct persona{
string nombre;
string apellido;
int edad;
};
int main()
{

cout<<"\n";
cout<<"\t \t \t PROGRAMA DATOS DE ALUMNOS";
cout<<endl<<"|--------------------------------------------------------------------------------------------------------|";
cout<<"\n";
cout<<"\n";
cout<<" INGRESA EL NOMBRE Y LA EDAD DE 30 ALUMNOS PARA SABER LA MEDIA, MEDIANA Y MODA REFERENTE A LA VARIABLE EDAD: ";
cout<<"\n";
cout<<endl<<"|********************************************************************************************************|";
cout<<"\n";
{

persona Estudiantes[30];
//INGRESO DE LOS DATOS DE LOS ALUMNOS
for(int e=0; e<30; e++)
{
cout<<"ingreso datos alumnos \t"<< e + 1;
cout<<"\n";
cout<<"ingreso nombre \t"; cin>>Estudiantes[e].nombre;
cout<<"ingreso apellido \t"; cin>>Estudiantes[e].apellido;
cout<<"ingreso edad \t"; cin>>Estudiantes[e].edad;
cout<<"\n";

};
int edad;
int media, moda, mediana, total;

for(int i=0; i<30; i++)
{
media=total/30;
total=edad;
cout<<"El calculo de la media es:";
cin>>media;
};

for(int j=0; j<30; j++)
{
mediana= total=edad;
cout<<"El calculo de la mediana es:";
cin>>mediana;
};

for(int k=0; k<30; k++)
{
moda=
total=total+edad;
cout<<"El calculo de la moda es:";
cin>>moda;

};

system("pause");
return 0;
}
}

Answer 5

ok thanks!
I try again..

Answer 6

Have a look at 'e'.

'e' is a for-loop counter

in this line it : "int Estudiantes[e].edad;"
It is used outside the loop and the compiler cannot find 'e'
for-loop counter only exist within the loop.

Also it is used in the i,j,k loop.
In these loop you not use i,j,k but 'e'

Answer 7

Please define in small steps what you want to do.

Create a list of 5 persons
persona Estudiantes[5];
done

Ask the use for input
for(int e=0; e<5; e++) { cout<<"ingreso datos alumnos \t"<< e + 1; cout<<"\n"; cout<<"ingreso nombre \t"; cin>>Estudiantes[e].nombre; cout<<"ingreso apellido \t"; cin>>Estudiantes[e].apellido; cout<<"ingreso edad \t"; cin>>Estudiantes[e].edad; cout<<"ingreso genero M/F \t"; cin>>Estudiantes[e].genero; cout<<"\n"; };
done

Now the list is filled with data and we can calculate with the data.

int Estudiantes[e].edad;
I do not understand what you want with this line.

"int" is the definition a new integer variable.
Estudiantes[e].edad is the 0,1,2,3,4 th element of the Estudiantes-array. (depending on the value of 'e')

Also this is strange. Here total is divided by 5 before a value is assigned

for(int i=0; i<5; i++)
{
media=total/5;
total=Estudiantes[e].edad;
cout<<"El calculo de la media es:";
cin>>media;
};

Please keep asking questions, you are doing well. It is a way of learning.

Read about for-loops and array's

Answer 8

That's part seems to be fine. It will be hard toe execute this in the playground nut on a laptop it is good.

Use a for-loop to show the data of the loop after user input.