What is wrong with this case?

Question

case '%':
cout << x % y;
break;

Answer 1

% only works or integers, but x and y are float in your code
You should cast them in this case.

Answer 2

Thanks)

Answer 3

write the link of the entire code

Answer 4

#include <iostream>
using namespace std;

int main()
{
float x, y;
char morgan;
string next;

do {

cout << "Input any number, arithmetic operator, any number: \n";
cin >> x >> morgan >> y;

switch(morgan)
{
case '*':
cout << x * y << endl;
break;

case '/':
cout << x / y << endl;
break;

case '+':
cout << x + y << endl;
break;

case '-':
cout << x - y << endl;
break;

case '=':
if (x == y)
{
cout << "True \n";
break;
}
else
{
cout << "False \n";
break;
}

/*
case '%':
cout << x % y;
break; */

}
cout << "You wont to continue? (yes/no) \n";
cin >> next;
}
while(next == "yes");

return 0;

}