it is working but i want expert way in which omit num<100e100 || num>100e-100 i used this in case of user give alphabetic input

Question

https://code.sololearn.com/WtYEGgop590X/?ref=app

Answer 1

Use !isNaN(num) as Number("y") returns NaN.

Answer 2

After finishing the courses here, move on to this site to extend your knowledge.
https://www.w3schools.com/

Answer 3

if (num!=0 && num<100e100 || num>100e-100 )
becomes
if (num!=0 && !isNaN(num) )

Answer 4

thanks it works where i learn all about js

Answer 5

thanks

Answer 6

i can't understand can you write here some line of code which should i change