Can anyone explain this to me?

Question

What is the output of this loop and if it gives nothing why ?!
If i is an integer and initialize to 1.

for(i<5;i=0;i++)
{
printf("%d",i);
}

Answer 1

Variable "i" needs to be declared as type int. You need somthing like..

for(int i = 0; i<5;i++){
printf("%d",i);
}

Answer 2

https://www.sololearn.com/learn/C/2927/

Answer 3

Assuming you had a main function and declared i around your loop. Your loop doesn't enter as i=0 is false so the exit condition was met. D_Stark fixed your loop to output 0 to 4.