no type checks on template specializations in c++

Question

When tweaking the code example for template specializations (https://code.sololearn.com/281/#cpp)

I came across some very surprising behaviour when using wrong type of argument, like:
MyClass<char> ob1(42);
MyClass<char> ob2(5.47);
No compiler error, no runtime error... I think this is something to think about when using this construct.

template < >
class MyClass<char> {
public:
MyClass (char x) {
cout <<x<<" is a char!"<<endl;
}
};

int main () {
MyClass<char> ob1(42);
MyClass<char> ob2(5.47);
MyClass<char> ob3('s');
}

output:
* is a char!
 is a char!
s is a char!

Answer 1

Well, a double can be implicitly converted to a char and if you use the specialized version of MyClass for a char then it's quite obvious that the char specialization is going to be used.