Java Pattern

Question

/*
Program to print the following pattern

1
0 1
1 0 1
0 1 0 1
1 0 1 0 1
*/

public class numpat
{
public static void main(String[] args)
{
for(int i=1; i<=5; i++)
{
for(int j=1; j<=i; j++)
{
//for every odd column print 1

if(j%2==1)
{
System.out.print(" 1 ");
}
else
{
System.out.print(" 0 ");
}
}
System.out.println();
}
}
}

What is wrong in the program?

Please correct the code and post it in the comment.

Answer 1

Some changes are made may be helpful
class NumPattern
{
public static void main(String s[])
{
int i, j;
int count = 1;
for (i = 1; i <= 5; i++)
{
for (j = 1; j <= i; j++)
{
System.out.format("%d", count++ % 2);
if (j == i && i != 5)
System.out.println("");
}

if (i % 2 == 0)
count = 1;
else
count = 0;
}
}
}

Answer 2

The error is in the inner loop ....
It will be:

for(int j=i;j>=1;j--)

Answer 3

To speed up your program processing, you can replace if-else part with:

System.out.print(j%2);