Explaination about what prod(i,j) i*j is doing and how the value of prod(x+2,y-1) we get? (ans for this code is 10)

Question

#define prod(i,j) i*j
int main() {
int x=3, y=4;
printf("%d \n",prod(x+2,y-1));
return 0;
}

Answer 1

It's not doing (x+2)(y-1) as expected but rather x+2*y-1 = 3+2*4-1 = 10

Answer 2

You're welcome. Happy coding!

Answer 3

Diego Acero thankyou for the Explaination :-)

Answer 4

Thanks! 😃Diego Acero