+ 8
Why this code prints 32 ?
#include <stdio.h> int recurse(int n){ if(n<=1) return 20; return(3+recurse(n-1)); } int main() { printf ("%d", recurse (5)); return 0; }
4 Respuestas
+ 8
recursive(5)=>
3+recursive(4)=>
3+3+recursive(3)=>
...
3+3+3+3+recursive(1)=>
3+3+3+3+20= 32
+ 6
recurse(5) calls recurse(4)
recurse(4) calls recurse(3)
...
recurse(2) calls recurse(1)
recurse(1) returns 20
recurse(2) now returns 20+3=23
recurse(3) now returns 23+3=26
...
recurse(5) Noe returns 29+3=32
main() method outputs 32.
That's how it works.
+ 1
The resource function will be invoked until de value of "n" is 1 ande it enters the if (n<=1) so that it returns 20 and ends, since it no longer invokes the function resource.
3+4=7
3+2=5
20
n=7+5+20
n=32
0
Bro. Thanks for this question. I was stuck asf. Thank you.