reduce method problem

Question

i learned that name[ i ] i is the index we cant pass string name alice or bob inside the square bracket
why allNames[ name ] name is the current value 'Alice' so on
var names = ['Alice', 'Bob', 'Tiff', 'Bruce', 'Alice'];
var countedNames = names.reduce(function (allNames, name) {
if (name in allNames) {
allNames[name]= allNames[name]+1;
}else {

allNames[name] = 1;
}
return allNames;
}, {});
console.log(countedNames)
console.log(names[0])

Answer 1

It's possible for allNames in the above code, to be a dictionary, where elements are stored as key-value pairs.

var dict = {
"one": 1,
"two": 2
};

The values can then be accessed using keys:

console.log(dict["one"])

Answer 2

I'm sorry, I don't know English well, and I didn't understand your question ...
But your code works)
Instead of "console.log(countedNames)" write this:
for (let i in countedNames)
     console.log (i + ": " + countedNames [i]);

Answer 3

Hatsy Rei so the initial value dictionary and the name considered as key is that the reason we can pass name key inside allNames and increment
allNames[name]