why does this not happen in this Cube code

Question

Hi there,
In this code:

x = int(input( ‘Enter an integer: ‘))
and = 0
while ans**3 < x:
ans = ans + 1
if ans**3 != x:
print(str(x) + ‘ is not a perfect cube’)
else:
print(‘Cube root of ‘ + str(x) + ‘ is ‘ + str(ans))

Why does the program not print each time the ans**3 is not equal to x?
For e.g the perfect cube of 1000 is 10. So technically it should print when ans is from 1-9 since the condition is ans**3 != (x)?

Answer 1

Don't use "and" as a variable name and replace all accents (`) with regular quotes (' or ").

If you want it to output that x is not a perfect cube each time (why?), you need to make the if statement a part of the while block by indenting it.