Why does this code gives 57 as output??

Question

https://code.sololearn.com/cpAuPnraFo79/?ref=app

Answer 1

n_ptr+5 coincidentally holds the value 0, so (n_ptr+*(n_ptr+5)) equals n_ptr+0 and points to the first element of the array

Answer 2

But when this statement is given,

printf("%d",*(n_ptr+*(n_ptr+4)));

The result is 0.
Why is it so?

Answer 3

You define an array with four elements and try to access its fifth element. The memory location could contain anything, possibly a trash value, possibly another variable's value. You can't really predict the outcome