Is there any other way

Question

#include <iostream>
#include<math.h>
using namespace std;

int main()
{ int x;
pow(x,3)=8;
cout<<x;
return 0;
}/*i have to find number which is powered by 3 is this correct way*/

Answer 1

x = pow(8, 1.0/3);

Yeah, so basically, you raise the resulting number to the power of the reciprocal of the power.

Answer 2

... Are you trying to find the cube root of 8?

Answer 3

This is a longer way.
https://code.sololearn.com/cd9tL43Oh5T6/?ref=app

Answer 4

I want the number which is about to power
if I know power
and result after powering that number

Answer 5

Just a tip: ensure that you use a double/float type (e.g. by using decimal points) in the exponent when using fractional powers such as in cube roots like what Hatsy Rei did.