Why this code has output 16??

Question

https://www.sololearn.com/post/83596/?ref=app

Answer 1

You use all kinds of loops in your own codes, so you seem to understand how they work.

Just think about what the loop does, step by step. Where does the loop begin, where does it stop? What happens if i==6? What happens in all other cases?

Answer 2

But here i have just used (FOR loop)

Answer 3

You use the same kind of loop on this code: https://code.sololearn.com/WCTFt1Mr0ZiK/?ref=app

Answer 4

If (i<=8)then i=8 will be added to sum and 17 will be printed as output or not??

Answer 5

Ok

Answer 6

The loop will go from i = 4 to 7
In each time it will ask if i = 6.
First, at i = 4, the if cond is not executed because it is false and it will just at the value of i to sum (0 + 4) now sum = 4.
now next i = 5, sum will be 4 + 5 = 9,
At i = 6, the if statement becomes true which will execute the statement "continue;" that will skip all the next statements in the loop at the current i run which will not add any value to the sum.
Lastly, i = 7 the if is not executed,
i will be added to sum wich will be 9+7=16
next i = 8 the loop's cond is false, the loop will not be executed.
The value 16 will be printed which is the value of sum ofcourse.

Hope that helped you out.
· Sorry for the big explanation :)

Answer 7

K i am gettimg u,r logic

Answer 8

No 24 will be printed if the loop's cond was (i <= 8)