Logical operator help!!!

Question

What is the output of this code?
a = 5
If !(a>2)
Print (“2”)
Elsif !(1+2==a)
Print (“3”)
Else
Print (“4”)
End

Why is the answer 3? Could some explain step by step? Please and thank you!!!

Answer 1

a>2 true because a = 5 and 5>2
But ! converts the true in false.
So, first print is skipped.
1+2=3==a is false but ! coverts false in true. So, program print 3

Answer 2

'!' is used for "not".

If not 'a' greater than 5 is the same as saying If 5 less than 2 which is false.

Elseif not 1+2 equal 5 is the same as saying If 3 not equal 5 which is true.

Be very careful using 'not' in programming. Whilst it certainly has it's use, I don't think I'd ever use it like the way you've shown.