Leap Year?

Question

x = int(input())
def leap_year(x):
if x % 400 == 0:
print("Is big leap year")
if x % 100 == 0:
print("is not leap year")
elif x % 4 == 0:
print("Is every 4")
leap_year(x)
Input: 1990
Output: no output

Okay, getting closer. Any idea who to tie the if statements together?

Answer 1

#leap.py
y=int(input("Enter year:"))
if y%4!=0:
print("Not a leap year")
elif y%100!=0:
print("This is a leap year")
elif y%400!=0:
print("This is not a leap year")
else:
print("This is a big leap year")

Answer 2

year = int(input())
#your code goes here

if year%400==0:
print('This a leap year')
elif year%4==0 and year%100!=0:
print('This is a leap year')
else:
print('This is a not a leap year')

Answer 3

year = int(input())
if year % 4 != 0:
print("Not a leap year")
elif year % 100 != 0:
print("Leap year")
elif year % 400 ==0:
print("Leap year")
else:
print("Not a leap year")

Answer 4

year = int(input())
if(year%4 == 0):
if(year%100 == 0):
if(year%400 == 0):
print("Leap year")
else:
print("Not a leap year")
else:
print("Leap year")
else:
print ("Not a leap year")