I want matrix M to output the value of G correctly please

Question

#include<conio.h>
#include<stdio.h>

int main()
{
int i,j;
int G[3][4] ={
{1, 2, 3, 9},
{0, 5, 2, 9},
{6, 4, 8, 8}
};
double B[3][4], M[3][4];

for (i=0; i<3; i++) {
for (j=0; j<4; j++){
(double) (G[3][4]);
G[3][4] = M[i][j];
}
}

for (i=0; i<3; i++) {
for (j=0; j<4; j++){
printf(" %2.2fl",&M[i][j]);
} printf("\n\n");
}

return 0;
}

Answer 1

Thanks very much I now understand

Answer 2

Thanks very much

Answer 3

I have corrected it but its still giving the same result.

#include<conio.h>
#include<stdio.h>

int main()
{
int i,j;
int G[3][4] ={
{1, 2, 3, 9},
{0, 5, 2, 9},
{6, 4, 8, 8}
};

int M[3][4];
for (i=0; i<3; i++) {
for (j=0; j<4; j++){

M[3][4] = (double) G[i][j];
}
}

for (i=0; i<3; i++) {
for (j=0; j<4; j++){
printf(" %2.2f",&M[i][j]);
} printf("\n\n");
}

return 0;
}

Answer 4

#include<conio.h>
#include<stdio.h>

int main()
{
int i,j;
int G[3][4] ={
{1, 2, 3, 9},
{0, 5, 2, 9},
{6, 4, 8, 8}
};

int M[3][4];
for (i=0; i<3; i++) {
for (j=0; j<4; j++){

M[i][j] = (double) G[i][j];
}
}

for (i=0; i<3; i++) {
for (j=0; j<4; j++){
printf(" %2.2f",M[i][j]);
} printf("\n\n");
}

return 0;
}

Answer 5

But it's still giving 0.00