Can this be done in less lines

Question

def test_func(x,y,z):
total = int(x+y+z)
if total == int(22):
return "Correct: " + str(total)
else:
if total < int(22):
incorrect = int(22) - total
print("Answer off by the integer of " + str(incorrect))
elif total > int(22):
incorrect2 = total - int(22)
print("Answer off by the integer of " + str(incorrect2))

Answer 1

2 lines

total=lambda x,y,z:'correct'+ str(x+y+z) if x+y+z==22 else "Answer off by the integer "+str(abs(22-(x+y+z)))
print(total(10,10,7))

Answer 2

Diego 1line
print(((lambda x,y,z:'correct'+ str(x+y+z) if x+y+z==22 else "Answer off by the integer "+str(abs(22-(x+y+z)))))(10,10,5))

Answer 3

def test_func(x,y,z):
total = int(x+y+z)
if total == int(22):
print("Correct: " + str(total))
elif total < 22:
print("Answer off by the integer of " + str(22 - total))
else:
print("Answer off by the integer of " + str(total - 22))

Answer 4

Thank you Mr. Böhler for your time. i will study this.

Answer 5

total=lambda x,y,z:'correct'+ str(x+y+z) if x+y+z==22 else "Answer off by the integer "+str(abs(22-(x+y+z)))
print(f'1:{total(10,10,7)}\n2:{total(12,8,2)}\n3:{total(5,15,5)}')

Answer 6

Three line version. You can even make it a oneliner.

def test_func(x,y,z):
total = int(x+y+z)
return "Correct: "+str(total) if total==22 else "Answer off by the integer "+str(abs(22-total))

Answer 7

abderrahim sallami

f=lambda t:t==22and"Correct: 22"or f"Answer off by integer {abs(22-t)}"

[print(f(sum(i)))for i in([1,1,20],[42,4,2],[10,10,5])]

Answer 8

Diego this gives no output for me

Answer 9

Paras finn
print(test_func(1,1,20))
print(test_func(42,4,2))

Answer 10

abderrahim sallami Your code is a oneliner. Only the function itself is counted.
PS: You can make it shorter.