Frequency of an int in array

Question

Hello! I have written a program on how to find the number that has a high frequency of appearances in an array but it doesn't work properly for every array I put. That is it gives me wrong output. If you could help me a bit with it.
https://code.sololearn.com/cEfmO5KOezDl/?ref=app

Answer 1

https://code.sololearn.com/cHHLHuLCuguQ/?ref=app

Answer 2

MargaritaK it works when you put curly braces after the if statement

Answer 3

MargaritaK You're welcome. I think the main issue was that *pos wasn't initialized

Answer 4

your welcome MargaritaK

Answer 5

line 45 remove I and put max, that should solve it

edit: the curly brace after the if should solve it

Answer 6

if(max<freq[i])
max=freq[i];
pos=&array[i];

==>

if(max<freq[i]) {
max=freq[i];
pos=&array[i];
}

Answer 7

MargaritaK What is your input? If I enter something like "1 2 3 4 4 5 6 7", it says "Number is 4" 👌

Answer 8

https://code.sololearn.com/c6OjsENk19gX/?ref=app

Answer 9

Anna thank you very very much, now I understand:)

Answer 10

*AsterisK* thank you

Answer 11

Anna it doesn't give me any output :(

Answer 12

*AsterisK* it kept giving me the wrong output:(

Answer 13

Anna if I enter "6 3 8 2 6 8 10 11" I get 11 when I want to get 8 because it is the largest number from the two (6,8) that appear 2 times in the array

Answer 14

Anna I see, seems like I didn't notice it. Thank you :)