Question about Boolean Operators (Java)

Question

I cannot get this code to run without error. I appreciate any help in this matter.

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner (System.in);

System.out.print(" are you over 18?");

int age = input.Int();

System.out.print("are you a female instrested in birth control?");

String gender = input.String();

if ( age >= 18 && gender == "female") {

System.out.print("Welcome to our site");

else System.out.println ("Sorry this site may be inapprobiate for you because it is about birth control");
}

}
}

Answer 1

You can't parse boolean that way(it will work if the string has "true" or "false" text. Also you cannot compare a boolean (gender) with a string, in that case you should compare gender with true (without quotes) or just put the variable name for testing it's content.
You can write:

Boolean gender = genderString == "female" ? true : false;

It's a simple way of setting an object's value depending on a condition.
Then:

if(age >= 18 && gender)

Answer 2

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner (System.in);

System.out.print(" are you over 18?");

int age = input.NextInt();

System.out.print("are you a female instrested in birth control?");

String gender = input.NextLine();

if ( age >= 18 && gender == "female") {

System.out.print("Welcome to our site");

else System.out.println ("Sorry this site may be inapprobiate for you because it is about birth control");
}

}
}

Answer 3

Is this better? It still gets errors but I put in the curly braces.

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner (System.in);

System.out.print(" are you over 18?");

int age = input.NextInt();

System.out.print("are you a female instrested in birth control?");

String gender = input.NextLine();

if ( age >= 18 && gender == "female") {

System.out.print("Welcome to our site"); }

else { System.out.println ("Sorry this site may be inapprobiate for you because it is about birth control");}

Answer 4

You still are writing "NextInt" instead of nextInt (the n should be lowercase), i think it's the only error.

The brackets are well, they're no strictly needed in this case (when the condition only executes one statement) but it's a good practice to always put brackets.

Answer 5

What do you think about this one? I get only one error at "=="

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner (System.in);

System.out.print(" are you over 18?");

int age = input.nextInt();

System.out.print("are you a female instrested in birth control?");

String genderString = input.nextLine();
Boolean gender = Boolean.parseBoolean(genderString);

if ( age >= 18 && gender == "true") {

System.out.print("Welcome to our site"); }

else { System.out.println ("Sorry this site may be inapprobiate for you because it is about birth control");}
}
}

Answer 6

The correct methods are input.nextInt() and input.nextLine()

Answer 7

You have to close the "if" brackets before the "else"

Answer 8

Also you may put brackets just after the else keyword and close after the block (in this case it's not needed because you just execute one function), example:
if(age>=18 && gender=="female"){
System.out.println("true");
} else {
System.out.println("false");
}

Answer 9

Hi there. Thank You for your response... I did what you said but I still get an error. Workspace points to the else as an error.