Hi everybody! Why the output of this code is 42 ?

Question

from __future__ import print_function
nums = [2,0]
result = map(lambda x: x + 2, nums)
print(*result, sep='')

Answer 1

Map, applies lambda on nums and adds 2 on its elements and returns the result in "result" list.
* operator extracts the result elements from [4, 2] to 4 2 form. And finally print with sep='' (which means that it should concatenate parameters) outputs it to 42 form.

Answer 2

(lambda x)=nums =>
=> nums+2 =>
=> 2+[2, 0] =>
=> 2+2, 2+0 =>
=> 4 2;
sep=' ' - removes a space between 4 and 2 => 42; 😊

Answer 3

Some might say it's because 42 is the answer to everything but that wouldn't be the right answer.

Answer 4

the reverse of this output :

nums = [2,0]
result = map(lambda x: x + 2, nums)
print(*reversed(list(result)),sep='')

Answer 5

BECAUSE U PROGRAMMED IT TO BE 42