Fill in the blanks to define a function that prints "Yes", if its parameter is an even number, and "No" otherwise. even(x):

Question

def
print
else

Answer 1

def
:
y

Answer 2

def is_even(int x):
if x%2==0:
print("Yes")
else:
print("No")

Answer 3

def is_even(x):
y = x/2
if int(y) == y:
return "yes"
else:
return "no"

Answer 4

If you think the question is wrong, you're right: just write the answer = else: then he accepts it as true...
correct spelling: else:
print("No")

Answer 5

def
:
else