What is output and why??

Question

Int x;
x=2,3,4,5;
Printf("%d",x);

Answer 1

If you lowercased your I the answer is 2.

What happens is that when you declare integers like:
int a, b, c, d;

a, b, c, d are all integer typed.

What if you want to assign a value?

int a=8, b, c, d=5;

Now what if you forget to store some variables?

int x = 2, {y=} 3, {z=} 4;

Here, imagine inserting a fictitious y and z and this whole statement makes sense.

Seriously that 3, 4, 5 are all useless and you don't need them.

Answer 2

Think you've encountered this question in the C challenges. Think you've got the answer but there was another question which is similar and I wanted to discuss it with you.
{Int x;
x=(2,3,4,5);
Printf("%d",x);}
Unlike your question this program outputs : 5
Because braces have been used.

Answer 3

It would be preferred if you ran these sort of codes in a C compiler.

Answer 4

First come first serve buddy 2 is first line hence it has the right to be the answer of this snippet 😅

Answer 5

First assignment i.e. 2 will be output.
You could give a try by yourself in c compiler.