int i=5,j; j=(++i)+(++i);

Question

The output of this code in Java and c compiler is different . Can anyone explain . Why is it so ?

Answer 1

It'll always be the same answer for C: undefined behavior

https://stackoverflow.com/questions/949433/why-are-these-constructs-using-pre-and-post-increment-undefined-behavior

Answer 2

Anna How nice it would be to have a bot to answer so many of these repeated questions?

I imagine this must be a mind bending discovery for people stumbling upon undefined behavior for the first time. Heck... I still remember thinking...

"What the Fraggle Rock?"

When I first stumbled upon it. It's like my mind was blown... 🤯 How could this be? 🤣

But, after seeing this happen to so many people for their first time, over and over and over again, it's sort of become like the movie Groundhog Day. 🤣

Answer 3

David Carroll "Fraggle Rock" - Haven't heard that one before. Had to look It up. It seems you are a child of the 80s. 😄

Answer 4

Thnk u so much Anna 😊

Answer 5

Michael U. Indeed sir... I am. 😉

I was 5 yrs old in 1980, so yep. 😁

Answer 6

ANSWER-13
first ++i is preincrement so the value of i is 6 another one also preincrement ++i the i value becomes 7 finally 6+7=13
THANK YOU