What is*f inthe following program

Question

Can you explain what is the use of%*f in the following
int a,b;
char c[10];
scanf("%2d %d %*f %5s",&a,&b,&c);
printf("\n %d%d%s",a,b,c);

i removed %*f in scanf and gave input
12
231456
tri
it is showing 12 231 456
can you explain why

Answer 1

The optional * will skip the input field.
so only var a and b will get value