Ple. Explain

Question

#define sqr(i) i*i
int main(){
printf ("%d%d", sqr (3), sqr (3+1));
}

Answer 1

Mohd Vais
#define macro is used to substitute the value written after macro so sqr(i) will replace by i×i
So when i value is (3+1) then due to macro substitution it will evaluate like 3+1×3+1 so 3+3+1=7 will return so output is 97

Answer 2

Macro definition will replace the source code directly. So the second output will be 7, because 3 + 1 * 3 + 1

Answer 3

What is output ?

Answer 4

explain what?