Why the output is 13??

Question

int x=3;
int y=(++x) +(x++)+(--x);

Answer 1

x was 3 first then
[(++x)=5
(x++)=4] //first section
[(--x)=4] //second section

Then output is 13

Answer 2

(++x)=(++3)= it is prefix which performs evaluation and assign value so now x=4

(X++)=(4++)= it is postfix it assigns value and performs evaluation now x=5

(--X)=(--5)= again it is prefix so it performs decrement operation and assigns value so now x=4

So now 4 + 5 + 4 =13

Answer 3

why so??

Answer 4

The output of that line is compiler dependent. The behaviour of a few ++ and -- in one line is undefined.

Answer 5

Here answer is 12 as we go through the code , code internally storing value of x, first ++x it preincreaments x by 1 and stores value of x as 4 and later again post increment by 1 now x is 5 and finally x is pre decrement by 1 that is now again x becomes 4. Post increment works like a temporary increase in value for next operation, ++x is 4 and actual value of x++ is 4 but as we have next operation it increments its value by 1 and x becomes 5 and now predecreament by 1 that is --x is 4 but while carrying out whole operation it is as below,

(++x)+(x++)+(--x)
(3+1)+(4)+((x++)-1)
4 + 4 + (5 - 1)
4+4+4 = 12

Code working as below , for understanding splitting code after each operation.

var x=3 {
document.write(++x); //4
document.write(x); //4
}

{
var x=3
document.write((++x)+(x++)); //8
document.write(x); //5
}

{
var x=3
document.write((++x)+(x++)+(--x)); // 12
document.write(x); //4
}

Answer 6

😁

Answer 7

It depends on the compiler. In C there is something called sequence points. When the execution reaches one of these points, it assures you that the collateral effects will be over, while C can evaluate the operations in the order it deems appropriate. This is because the compiler looks for the most efficient way to execute the code.

Answer 8

The answer is;
++x=(1+3)=4
X++=(4+1)=5
--x=(5-1)=4

Final. y=4+5+4=13.

Answer 9

O/p shd be 12.. not 13!

Answer 10

Here x=3 initially.
++3 which is a prefix notation assigns it as x=4.
x++ which is a postfix notation uses x=4 but after the use it assigns x=5.
Finally --x is also prefix notation thus it assigns x=4.
Therefore result y=4+5+4=13.

Answer 11

The answer is 4.
++x = 4
x++=4 (post increment)
-x =-4
Answer = 4+4-4=4 IMHO 🤗🤗 🤗