+ 3

Help

https://www.sololearn.com/Discuss/1953430/help-please number = float(input("Please enter ur number:\n")) if (number) < 50: print(f"Your number {number} < 50") if (number) > 50: print(f"Your number {number} > 50") except ValueError: print("Please enter a number") error: line 11 except ValueError: ^ SyntaxError: invalid syntax

2nd Sep 2019, 12:27 PM
Arya
Arya - avatar
5 Respuestas
+ 3
Here's a correct code. I've made some changes: - If you want to use 'except', you have to use 'try' first. - ValueError must be in brackets as an "except" 's argument. https://code.sololearn.com/cFR86fpMdAEF/?ref=app
2nd Sep 2019, 12:51 PM
Krzysiek
Krzysiek - avatar
+ 1
Arya i missed the coverting input into float... I corrected it check again..
3rd Sep 2019, 7:21 AM
Sgk101
Sgk101 - avatar
0
thanks buddy, is there another way to write ? for example like this?
2nd Sep 2019, 1:53 PM
Arya
Arya - avatar
0
If is not a loop statement hence there is no need of break (break is used to get out of loop)  three basic types of control structures: Sequential: default mode. Sequential execution of code statements (one line after another) -- like following a recipe Selection: used for decisions, branching -- choosing between 2 or more alternative paths. In C++, these are the types of selection statements: if if/else switch Repetition: used for looping, i.e. repeating a piece of code multiple times in a row. In C++, there are three types of loops: while do/while for Here is my modified code... Hope it will help you https://code.sololearn.com/crVtXIi3TyJs/?ref=app
2nd Sep 2019, 6:27 PM
Sgk101
Sgk101 - avatar
0
Sgk101 hi this wont work, because input type is always str i couldn't find anything else
2nd Sep 2019, 8:33 PM
Arya
Arya - avatar