Tuple & int comparisons in python3

Question

How to syntax-express a tuple & int comparisons in python3? Please help

Answer 1

Well try:

items = [
  ("product1", 10),
  ("product2", 9),
  ("product3", 12),
]

filterers = []
for filterer in items:
  if filterer[1] >= 10:
    filterers.append(filterer)
print(filterers)

Answer 2

As in, what is different between tuples and ints?

Answer 3

What do you want to know

Answer 4

You can't always compare integers to tuples because program does not know how do you want to compare them.

For example: (24, 8, 2, 11) > 17
It could mean:
~Length of (24, 8, 2, 11) is greater than 17.
~All the items in (24, 8, 2, 11) are greater than 17.
~Atleast one item in (24, 8, 2, 11) is greater than 17.
~Sum of (24, 8, 2, 11) is greater than 17.

Program does not simply know.
Thus programmer needs to find a way to change (24, 8, 2, 11) into integer.
Solutions for previous examples:
~len((24, 8, 2, 11)) > 17
~min((24, 8, 2, 11)) > 17
~max((24, 8, 2, 11)) > 17
~sum((24, 8, 2, 11)) > 17

(Just luck they all got solved with just builtin functions. 🍀)

Answer 5

Oh wow, Seb TheS, big thanks to you, it works now

Answer 6

Well...
Prometheus,Cbr,Finn Styles:
Thanks all, integers are numbers and tuples are collections, yes I know it, but still how to pull an index spot from a tuple so I could compare it with ints... Like this:

Items = ("Price 7", 25)
Pricings = [ ]
For pricing in items:
If pricing >= 25:
Pricings.append(pricing [1])
Print(Pricings)

The above code cannot execute due to comparison issues, but let me say that I need that near to exact code to work, so please avoid maps and lists comprehensions... Help please

Answer 7

Seb TheS,
Thanks, but I need it to be iterable as well

Or how to get tuple's index and iterate through it?

Answer 8

Nontakeinvain .com Your question was little unclear, but here might be 2 wanted solutions:
t = (24, 8, 2, 11)

#When item indices aren't required:
for el in t:
print(el)

Output:
24
8
2
11

#When item indices are required:
for i in range(len(t)):
print(i, t[i])

Output:
0 24
1 8
2 2
3 11

Answer 9

You can perform each task I mentioned similarly for lists aswell.

Answer 10

Seb TheS,
Thanks, but I need the loop to contain a comparison of a tuple to int
If t == el:

Answer 11

You have to use index value through for loop while checking for the no. in the tuple is an integer or not,for this
For i in range(len(tuple)):
If tuplename[i]==integer:
Or..
For i in tuple:
if i==integer :
Hope this helps

Answer 12

Thanks Finn Styles,
But it doesn't work...

Answer 13

This is my original code (isn't working), which I want to preserve as is:

items = [
  ("product1", 10),
  ("product2", 9),
  ("product3", 12),
]

z = list(len(items))

filterers = []
for filterer in z:
  if filterer >= 10:
    filterers.append(filterer)
print(filterers)

Answer 14

list(len(items)) -> list(3) -> error

What you wanted to do with variable z?

What did you mean with list(len(items))

Answer 15

Seb TheS, z helps the code to be more readable.

I hoped list() would make the non-itetables iterable.

items = [
  ("product1", 10),
  ("product2", 9),
  ("product3", 12),
]

z = len(items)

filterers = []
for filterer in z:
  if filterer >= 10:
    filterers.append(filterer)
print(filterers)