How to resolve this error?

Question

#include <stdio.h>

int main() {
int x = 10, y = 12;
char * a;
a = &x;
x = 1xab;
printf("%d%d", x, * a);
return 0;
}

And please explain the reason of error too

Answer 1

x = 1xab;
This is not a valid syntactically. I'm not sure what you expected out of this.

a = &x;
You are assigning an address that points to a incompatible data type. Char pointer here can only point to a one byte data, while the data itself is int (commonly four bytes data).

Answer 2

You not define
Variable ----> b
Are you multiply in
x = 1xab or 1*a*b