How do you explain the following function?

Question

Please help me understand how the last line in the read () function in cpp below does not let the 0 to be counted?

void read (int a[], int& n);
cout<< “Enter integers. Terminate with 0: \n”;
n=0;
do{
cout<< “a[“<<n<<“]: “;
cin >> a[n];
}
while (a[n++] !=0 && n<100 );
- - n;

Answer 1

It is perfectly working...
If you want to print last 0 also , then just remove n--;
In read function...
https://code.sololearn.com/cX0nY2yPVr5e/?ref=app
here you are taking size variable reference as argument so changes in the function affects original value.

Answer 2

Its better to show full code.. Or run it in the play ground and share link here..
Are you taking about
a[n++]!=0
If yes, some times it depends on the compiler. So specify clearly..

Answer 3

what is the purpose of the read() function?

Answer 4

The entire code is:

#include <iostream>

using namespace std;

void read(int [], int&);
void print( int [], int);
long sum (int [], int);
const int MAXSIZE=100;

int main(){
int a[MAXSIZE]={0}, size;
read (a,size);
cout << "The array has " <<size <<" elements: ";
print (a,size);
}

void read(int a[], int& n){
cout <<"Enter integers. Terminate with 0: \n";
n=0;
do{
cout << "a ["<<n<<"]: ";
cin >> a[n];
}
while (a[n++] !=0 && n<MAXSIZE);
--n;
}
void print (int a[], int n){
for (int i=0; i<n; i++)
cout <<a[i]<<" ";
cout<<endl;

}

Answer 5

you have a | do{} while | loop in your code, that's the problem, it will not work in playground, because it's not a real terminal. it will not wait for you to enter 0 to terminate.
try your code on a computer.

Answer 6

@ Jaya Krishna Thanks. Sorry but I think I have not asked my question clearly. I want to know how the line (--n) prevents the reading of 0. As an explanation for this line I have (//don't count the 0).

Answer 7

Jack
Its ok. Fine... And Wel come