Can anyone explain this error in c

Question

Which of the line gives an error in the below code snippet and why??

#include<stdio.h>
main()
{
const char* foo = "hi"; //line1
foo ="hello"; //line2
foo[0]=1; //line3
}

Answer 1

Akshay Jain
You declared foo as pointing to a const char, so you can't change it. And you are assigning value to const char which is an predefined read only memory so that's why line 3 containing error second error which rises from this is integer to character assignment which may leads to problem so the line 3 is which contains error and sane instance in line 2 where only pointer is pointing to hello so it will print hello so only line 3 which contains error

Answer 2

Akshay Jain yeah the error is in 3 line that's an typo look answer 2 line is pointer is pointing to other string and line is assigning the constant read only memory location which is cause of error

Answer 3

GAWEN STEASY
Thanks for the answer but on compiling the error occurs only in third line not in second one.
This is a bit confusing then!