We haven't exitted from the outer loop, then how we got result....

Question

1 def check_sum(num_list):
2. for n1 in num_list:
3. for n2 in num_list:
4. if n1 + n2 == 0:
5. return True
6. return False
7. num_list = [10,-14,26,5,-3,13,-5]
8. print(check_sum(num_list))

output = True

Answer 1

Add double dots after 0. Then it will not give any error.

if n1 + n2 == 0:

Answer 2

One typical pattern to break out of a double loop is this:

flag = False
for...
for...
if break_condition:
flag = True
break
if flag:
break

Answer 3

amith if inner loop results in True
the line 6 does not get executed because the function exits with return True.
line 6 gets executed when both loop end with False.

Answer 4

@molang
code exitted from inner loop when n1 + n2 becomes zero.... but code haven't exitted from outer loop..... no statement is provided for exitting from outer loop... then how line 6 get executed