Multiple elif statements show invalid syntax

Question

I have some code with like 10 elif statements, and when I try to run it, it marks invalid syntax in the 6th statement, but I already checked it and it seems correct.
Its like:

if x == 1:
some code
elif x ==2:
some code
elif x ==3:
some code
elif x ==4:
some code
elif x ==5:
some code
elif x ==6:
some code
elif x ==7: <---Invalid Syntax
some code
elif x ==8:
some code
elif x ==9:
some code
elif x ==10:
some code
elif x ==11:
some code
else:
print(error)

Answer 1

Yes, invalid syntax means you perhaps forgot to close a quotation, bracket or parenthesis. Try it on CodePlayground and see what happens ;)

Answer 2

I agree with @Mike L. however, instead of using a huge if-elif statement to test a bunch values, I would suggest using a dictionary. Dictionaries are powerful objects in python and you can use them in various ways. In this case, we can use them as a switch

def checkX(x):
d={0:"arg0", 1:"arg1", 2:"arg2"}
return d[x]

print(checkX(2))
#output: arg2

you can even store references to functions in dictionaries:

def func(n)
return n*2

d={0:func,1:func,2:func}

def checkX(x):
return d[x](x)

print(checkX(1))
#output: 2

I use this method all the time for event handling where you need to test for loads of different cases.

Answer 3

Your if-else tree seems to be okay. If you're getting an error, it is probably the line before the elif statement.

Answer 4

Thank you, problem solved :)