The Spy Life from code couch. Help

Question

import re
text = str(input())
result = re.sub(r"[^\w]", "", text, flags=re.I)
res = re.sub(r"\d", "", result, flags=re.I)

def reverse(res):
res = res[::-1]
return res

print (reverse(res))

#how can i not delete the spaces, without mentioning each symbol to remove?

Answer 1

I found it at last.
https://code.sololearn.com/ctKXCQL5E0Zv/?ref=app

Answer 2

Instead of trying to delete you can find just the strings and spaces instead. For example

import re
inp = input()
print(''.join(re.findall(r'[a-zA-Z]|\s', inp[::-1])))

Answer 3

This was my answer:

https://code.sololearn.com/ci6RSHBA024d/?ref=app

Answer 4

My solution of "The Spy Life":

code_text = input()
uncode_text = ""

number = -1

while number >= -(len(code_text)):
if code_text[number].isalpha() == True or code_text[number].isspace():
uncode_text += code_text[number]
number -= 1

print(uncode_text)

What are You thinking about?

Answer 5

My code :)

https://code.sololearn.com/c5qv6PFMxGko/#py

Answer 6

Not fancy but it works :

x=input()
y=x[::-1]
z='abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ '

for i in y:
if i in z:
print(i, end='')
else:
print('', end='')

Answer 7

num=input()
alph="abcdefghijklmnopqrstuvwxyz"
p=""
q=""
for i in num:
if i==" ":
p+=" "
if i in alph:
p+=i
for k in range(len(p)):
q+=p[-k-1]
print(q)

Answer 8

This works too:
import re

txt = input()

pattern = r'[a-zA-Z\s]'

ans = re.findall(pattern, txt)

anss = ans.reverse()

print("".join(ans))

Answer 9

import re
x=input()
x=re.sub('[^a-zA-Z\s]', '',x)[::-1]
print(x)

Answer 10

Nowadays, it is very easy to follow someone else's life using social networks or a smartphone. I am very worried about this and I am afraid of hackers who are everywhere, so I use the recommendations https://theteensafe.com/iphone-keylogger/ , there is everything about the protection of all social networks and the smartphone. I found it useful and I want to share it with you.

Answer 11

import re
encrypt=input()
pattern=re.compile("^[a-zA-Z\s]")
w=[]
c=0
for i in encrypt:
match=re.search(pattern,i)
if match:
w.append(i)
c+=1
w.reverse()
print("".join(w))

Answer 12

This code I wrote to validate my answer