0
My code :/
S=1 + 2/(1+(1/2))+...+n/(1+1/2+1/3+...+1/n) Input: n=2 Output will show: 2.333 (or 7/3) But my code show: 3 :v https://code.sololearn.com/cyZvzIgU3WF3/?ref=app
3 Respuestas
+ 1
you are doing integer division
the type of the "1" in the expression ( line 11 ) is int, and the type of " i " is int.
in c++ if both of the operands are integers, the division operator performs integer division instead. integer division drops any fractions and returns an integer value.
so you need at least one of the types involved to be floating point (float or double) in order for floating point division to occur.
try the following and it will work as expected:
#include <iostream>
using namespace std;
int main() {
int n;
cin>>n;
float s=0;
float p=0;
if (n>0){
for (int i=1;i<=n;i++){
s=s+1.f/i;
p=p+i/s;
}
}
cout<<p;
return 0;
}
+ 1
integer to floating point conversion ( functional cast expression ) can also gives you same result
0
Thank you
I fix
s=s+ float(1)/i;
p=p+ float(i)/s;
And it show the same answer 1.f/i
Why ?