can someone help solve this:what is the output of this; class A { public: A () { cout << "a";} ~A () { cout << "b" ;} }; class B public: B () { cout << "c" ;} ~B () {cout << "d" } }; int main () { B b A a };

Answer 1

cabd
first constructor of class B gets invoked followed by constructor of class A.
then, in the opposite direction destructor of class A gets invoked first followed by that of B.

Answer 2

cabd because the constructor are in call of class priority same as destructor are work depends to the end of the constructor

Answer 3

cabd