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Write a program in c to enter 20 number in an array. Determine the sum of odd numbers and even numbers separately
4 Respuestas
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If you think of it a little bit, then you'll get it!
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#include <stdio.h>
main(){
int ar[]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
int even=0,odd=0;
for(int i=0;i<20;i++){
if(ar[i]%2==0)
even+=ar[i];
else
odd+=ar[i];
}
printf("sum of even numbers=%d\n",even);
printf("sum of odd numbers=%d",odd);
}
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thanks
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This problem is similar to finding the sum of all odd and even numbers between 1 to using for loop.
Here is the sample C program to find sum of all even numbers
for(counter = 1; counter <= N; counter++) {
/* Even numbers are divisible by 2 */
if(counter%2 == 0) {
/* counter is even, add it to sum */
sum = sum + counter;
}
}
Source : http://www.techcrashcourse.com/2015/11/c-program-to-find-sum-of-even-numbers-from-1-to-N.html
Here is the sample C program to find sum of all odd numbers
for(counter = 1; counter <= N; counter++) {
/* Odd numbers are not divisible by 2 */
if(counter%2 == 1) {
/* counter is odd, add it to sum */
sum = sum + counter;
}
}
Source : http://www.techcrashcourse.com/2015/11/c-program-to-find-sum-of-odd-numbers-from-1-to-N.html