Swap 2 Nibbles in a byte & find the output of the swapped Nibbles after converting a Decimal Number to a Binary Number.

Question

Given a byte, swap the two nibbles in it.
For example 100 is to be represented as
01100100 in a byte (or 8 bits).
The two nibbles are (0110) and (0100). If we swap the two nibbles, we get 01000110 which is 70 in decimal.
But, for smaller numbers that are less than 8 bits, need to be added extra zeros in the front.

I am strucked with how to push extra zeros after splitting the obtained binary number & swap the two numbers. I am getting the binary output, but the splitting is not working.

Anyone please help?

Here's my code:

def dec(n):
if n==0 or n==1:
print(n,end="")
return
dec(int(n/2)), dec(n%2)
n1= str(dec(10))
st=n1.split()
if len(st)<8:
st.format(0,8)
s=st[4:8]+s[0:4]
print(s)

Answer 1

Thank you Alexandr. Could you please answer without any built-in functions

Answer 2

Wow. This was so quick.