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Usin arrays write a program that inputs five numbers and if there are any zeros, removes them and shows the app nput without 0s.
My attempt so far #include <iostream> using namespace std; int main() { int i = 0; int num[5]; for (int j = 1; j < 6; j++) { cout << "Enter number [" << j << "]= " << endl; cin >> i; } for (int j = 0; j < 5; j++) { if (i!='0') { i++; } } cout << "Non zero: " << endl; for (int i= 0; i < 5; i++) { cout << num[i] << "\t"; } return 0; }
7 Respuestas
0
int main(){
int numbers[5];
int counter = 0, i = 0;
for (int j = 0; j < 5; j++)
{
cout << "Enter number [\" << j << \"]= " << endl;
cin >> i;
numbers[j] = i;
}
for(int x = 0;x < 5;x++)
if(numbers[x] != 0)
counter++;
int numbers2[counter]; // declare a second array to the size of non-zero count
for(int x = 0,z = 0; x < 5; x++)
if(numbers[x] != 0){
numbers2[z] = numbers[x];
z++;
}
for(int x = 0; x < counter; x++)
cout << numbere2[x] << ',';
return 0;
}
+ 1
blackwinter thank you so much. you have no idea how helpful you’ve been.
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Thanks. unfortunately it doesn’t. If there was a way that I could keep the first and last for and change the middle for it would be great.
0
if your looking to actually remove the zeros then, I would use a vector.
http://www.cplusplus.com/reference/vector/vector/
edit:-
On second thoughts.... I would use list:-
http://www.cplusplus.com/reference/list/list/
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how can I store non zero elemnts? sorry I’m so new at this.
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@blackwinter
your method requires you to declare a seconds "empty" array of the same size as the first..now if you assign all the non-zeros to this second array, all of the other elements will be assigned a default value of....guess what?....zeros.
0
rodwynnejones do you have any other way to do this?