List index return not valid

Question

When requesting index values from a list with identical items, the index value returned is not from the iteration, but from the first occurrence of list item.
Is there a way to ascertain the index value of the repeated item?
Code sample attached for clarification
https://code.sololearn.com/cl13DK0N8pUi/?ref=app

Answer 1

I don't think there is a way around it, maybe if you do it manually

Answer 2

Hi ✳AsterisK✳
Jay Matthews has embedded a code in a reply to my sample code which shows a work around.
Thanks for taking the time to look into it. 👍

Answer 3

I know this is a late reply but...
List index method can take three params.....one of which is the starting index.
myint = 4
mylist = [1, 2, 3, 4, 5, 1, 2, 3, 4, 5]
print(mylist.index(myint))
print(mylist.index(myint, mylist.index(myint)+1)) <- return 8, index of second '4'.

For more info:-https://docs.python.org/3/tutorial/datastructures.html

Answer 4

rodwynnejones Thanks. I will play with this also

Answer 5

Thanks to Jay Matthews for his solution

Answer 6

Thanks Coder Kitten
Another great idea for me to play with.