Help! Deja Vu Challenge using Python 3. Edit the code below please!

Question

user_input = input(": ")
if user_input==str:
c=[]
for i in len((user_input) -1):
user_input[i]+=c
for y in len((c)-1):
if c[y]==y+1:
print("Deja Vu")
else:
print("Unique")

Answer 1

For python:
myList = list(input())

if any ([myList.count(i) > 1 for i in myList]):
print("Deja Vu")
elif all ([myList.count(i) == 1 for i in myList]):
print("Unique")

Answer 2

scrap it all and start again...
Think about sets...what happens when you put a string in a set?

Answer 3

Alexandr, What is PEP 8? and why doesn't it return anything? Why only ": "? How is it going to take input the code?

Answer 4

rodwynnejones, is there any way except sets? Because i haven't reached that level! I am on try and exceptions

Answer 5

myList = list(input())
count = 0
for x in myList:
n = myList.count(x)
if n > 1:
print("Deja Vu")
count = 0
exit()
else:
count += 1
if count > 0:
print("Unique")

Answer 6

Loop through the string and use the string count() method.

Answer 7

print((lambda i:'Unique' if sorted(i)==sorted(set(i)) else 'Deja Vu')(input()))

Answer 8

# Take input as a string and store it in a list
type = list(input())

# Initialize an empty set variable e to store unique characters
e = {""}

# Iterate over each character in the input
for i in type:
# Add the character to the set e
e.add(i)

# Check if the length of the set e minus 1 is equal to the length of the input
# If it is, all characters are unique, so print "Unique"
# Otherwise, there are duplicate characters, so print "Deja Vu"
print('Unique') if len(e)-1 == len(type) else print("Deja Vu")