Security Code Coach Problem in Python

Question

I have just started to learn Python and am finding it a lot easier than Java to just pick up and run with. Here’s my first Code Coach solution - which seemed a lot easier than the Hard rating it was given! Is there anything I could do to make it simpler still? Or to use better practice? Thanks!

https://code.sololearn.com/cZD4VQ6we4sn/?ref=app

Answer 1

My code:

string = input()
situation = string.replace("x", "")
if "Tquot; in situation or "$T" in situation:
print("ALARM")
else:
print("quiet")

Answer 2

Honestly that's clever KnuckleBars! I didn't think about that!

Answer 3

My solution feels like cheating! I just remove all the x and then an if statement if you can find $T ot T$

Answer 4

Check out 👇

s=input()
a=0
for i in range(len(s)-1):
if s[i] =='#x27;or s[i]=='T':
for j in range(i+1,len(s)):
if s[j]=='G':
a=1
break
elif s[j]=='T' or s[j]=='#x27;:
a=2
break

if a==1:
print ("quiet")
break
elif a==2:
print("ALARM")
break

Answer 5

It’s not cheating if it works!That’ what I posted for...to see others workarounds and ideas!

Answer 6

stripped = input().replace('x','')
print("ALARM" if "$T" in stripped or 'T#x27; in stripped else 'quiet')

Answer 7

This is how I made mine simple if you're interested:

x = ''.join(input().split('x'))

y = ''.join(x.split('T#x27;))
z = ''.join(y.split('$T'))

print('ALARM'if '#x27; not in z else 'quiet')

Noob style: passes all tests.
#x removes space.
#y&z remove only the thieves with money
#If money is gone an alarm
#else - it's all quiet

Answer 8

inp = input()
a_list = list(inp)
x =[i for i,d in enumerate(a_list) if d=='G']
G = x[-1]
S = a_list.index("quot;)
y =[i for i,d in enumerate(a_list) if d== 'T']
T = y[0]
if G < S < T or G > S > T:
print("ALARM")

elif S > G > T or S < G < T:
print("quiet")

Answer 9

import re

entry = input()
diagram = re.sub("[x]", "" ,entry)

if "G$T" in diagram or "T$G" in diagram:
print("ALARM")
else:
print("quiet")

Answer 10

import re

def floorvalidate(floor):
pattern1 = r"Tx*\quot;
pattern2 = r"\$x*T"

thief_money = re.search(pattern1, floor)
money_thief = re.search(pattern2, floor)

if thief_money or money_thief:
return "ALARM"
else:
return "quiet"

floor_layout = input()

Answer 11

outcomes = dict(
G = {
"G": "hello friend!",
"S": "wish I'd had this money",
"T": "go away thief!"
},
S = {
"G": "move along",
"T": "fu.. he's gonna take me"
},
T = {
"G": "fu.. the guards!",
"S": "payday"
}
)

value = input().replace("x", "").replace("quot;, "S")
value += "G" + value[::-1]

cases = []
for cur,upcoming in zip(value[:-1], value[1:]):
outcome = outcomes[cur][upcoming]
cases.append(outcome)

res = {
1: "ALARM",
0: "quiet"
}

switch = 0
if "payday" in cases or "fu.. he's gonna take me" in cases:
switch = 1

print(res[switch])