Int main(){int a; a=31&14+5*sizeof(6.4);printf("%d",a) } output=2 how?????

Answer 1

About the single & it is bitwise AND operator. SoloLearn got a good intro on that subject here

https://www.sololearn.com/learn/4070/?ref=app

P.S. You can edit your text bro, no need to post a typo fix as another text reply : )

Answer 2

Are you sure the output was 2? I think it's rather 22 though.

* Having known the default type used for floating point literal is double, assume sizeof(double) = 8.

31 & 14 + (5 * sizeof(6.4))
31 & 14 + (5 * 8)
31 & 14 + (40)
31 & (14 + 40)
31 & (54)

Final result: 22

Dec Binary
31 00011111
54 00110110
----------------------- &
22 00010110

I could be wrong though;

Answer 3

It could be the book mistake I don't know but I think your explanation is right thnku

Answer 4

I got 22 for output of the code bro ...
Try to run it in Code Playground, you'll see ...

Answer 5

Is this type of questions you can expect in your coding test placements

Answer 6

Didn't you say "the book mistake"?
I don't know about placements, but looks common for a challenge.

Answer 7

What is single & b/w 31 and 44 means

Answer 8

14*