Increment in C Programming Language

Question

why the result is not what it should be in follow example:

https://code.sololearn.com/coXVMi3i87fh/#c

#include <stdio.h>

int main(){
int x, y, m;
x = 10;
y = 15;
// y++;
m = ++x + y++;
printf("x is %d", x);
printf("\ny is %d", y);
printf("\nResult is %d", m);
printf("\nx is %d", x);
printf("\ny is %d", y);
return 0;
}

// OUTPUT
// x is 11
// y is 16
// Result is 26
// x is 11
// y is 16

Answer 1

@Dolan Hêriş
no,
++x is preincrement, which means that x will be incremented before statement m = ++x + y++;
y++ is postincrement, which means that y will be incremented after statement m = ++x + y++;

again, m = ++x + y++; will be executed in the follow steps:
1. x is incremented by 1 (as it is preincrement) x = x + 1 = 11
2. addition of x and y (x was incremented = 11, but y was not incremented = 15) m = 11 + 15 = 26
3. y is incremented by 1 (as it is postincrement) y = y + 1 = 16

Answer 2

The result is exactly what it should be

You can write statement m = ++x + y++; as follows:

x = x + 1; // x = 10 + 1 = 11
m = x + y; // m = 11 + 15 = 26
y = y + 1; // y = 15 + 1 = 16

Answer 3

@Dolan Hêriş, you are welcome

Answer 4

andriy kan Thanks. the (y++ = 16). the (x++ = 11), so the result supposed to be 27.

why one added to the variable X but not added to the Y?
m = ++x + y++
m = 11 + 16 —> 27

Answer 5

thank you my friend. andriy kan