need explonation in detail

Question

step by step needed, confused

#include <stdio.h>
void fun(int *i,int *j)
{
*i=*i * *i;
*i=*j * *j;
}
int main()
{
int i=2,j=3;
fun(&i,&i);
printf("%d,%d",i,j);
return 0;
}

Answer 1

#include <stdio.h>
void fun(int *i,int *j)// i and j store the value of main method i variable means i=2 and j=2
{
*i=*i * *i;//i=4
*i=*j * *j;//i=16
}
int main()
{
int i=2,j=3;
fun(&i,&i);//call by reference fun(addr of i,addr of i)
printf("%d,%d",i,j);//16 and 3
return 0;
}
Explanations:
i=2
fun(&i,&i);
fun(int *a , int *b) is stored the address of main method i variable and if the value of a and b change in fun() than the value of i is also change
*a=*a**a;//value of i =4
*a=*b**b;//value of i=4 than b=4*4 ,*a =16 and now i is 16

Answer 2

Yes

Answer 3

so here single variable address is assinged to two different pointers(i and j) right