How to display all details of employees.? If you add two employees information then why display last employee information.?

Question

https://code.sololearn.com/c7iSVP2Qeroa/?ref=app

Answer 1

Shrikant Khurd You have to store employees information in an arraylist.

According to your code previous employees data overided by latest employee data. So in this case you will always get last data.

Make a class Employee with attributes id and name.

You can do like this :-
----------------------------------
ArrayList<Employee> list = new ArrayList<Employee>();

Employee e = new Employee();

e.setId(1);
e.setName("AJ");

list.add(e);

Employee e1 = new Employee();

e1.setId(2);
e1.setName("Anant");

list.add(e1);

------------------------
To display all data just iterate the list like this:-

for(Employee e : list) {
System.out.println(e.getId() + " " + e.getName());
}

Answer 2

Please tell me logic and how to display all employees details.?

Answer 3

create class Employee and array of this Employee objects.

// create class Employee
class Employee {
int id;
String name;

Employee (int id,String name ){this.id=id; this.name =name; }
}

//use one Scanner for Sololearn
//add Employee[] array declaration
class Information {
...
//Information in[]=new Information[100];
Employee employee[]=new Employee[5]; // but ArrayList is better
Scanner in=new Scanner("1 Anton\n123 1 Michael\n124 2 3"); //System.in

public int choice() {
System.out.println("Enter your option :");
//ch=s.nextInt();
ch=in.nextInt();
...
//case 1
employee[InfoCount] = new Employee(id,name); //added
InfoCount++;
...
} while( ch != 3 );
//return choice();
return ch;

void putData() {
for(int i=0;i<InfoCount;i++) {
/* System.out.println("Employee id :"+id);
System.out.println("Employee name :"+name); */

System.out.println("Employee id :" +employee[i].id);
System.out.println("Employee name :" +employee[i].name);